cola70 cola70
  • 15-08-2019
  • Mathematics
contestada

h(x) = sqrt of x²+x+3
find : h(x+2)

Respuesta :

jdoe0001 jdoe0001
  • 15-08-2019

[tex]\bf h(x)=\sqrt{x^2+x+3}\implies h(x+2)=\sqrt{(x+2)^2+(x+2)+3} \\\\\\ h(x+2)=\sqrt{\stackrel{FOIL}{(x^2+2x+4)}+x+2+3}\implies h(x+2)=\sqrt{x^2+3x=9}[/tex]

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