Explanation:
It is given that,
Voltage of the battery, V = 12 V
Current, I = 100 ampere-hours
Energy stored is given by the product of power and time taken. So,
[tex]E=P\times t[/tex]
P is the power, [tex]P=V\times I[/tex]
[tex]P=12\times 100[/tex]
P = 1200 watts
This power can be used for 1 hour or 3600 seconds
Energy, [tex]E=1200\times 3600[/tex]
E = 4320000 J
So, the energy stored in this battery is 4320000 J. Hence, this is the required solution.
