The vertex of the parabola [tex]y=ax^2+bx+c[/tex] has the coordinates:
- [tex]x_v=-\dfrac{b}{2a};[/tex]
- [tex]y_v=ax_v^2+bx_v+c.[/tex]
Therfore, the vertex of the parabola [tex]y=x^2+6x+2[/tex] has coordinates
[tex]x_v=-\dfrac{6}{2}=-3[/tex]
and
[tex]y_v=(-3)^2+6\cdot (-3)+2=9-18+2=-7.[/tex]
Answer: (-3,-7)
