Answer: II, C
[tex]-\frac{\pi}{3}[/tex]
Add 2π (which equals [tex]\frac{6\pi}{3}[/tex]) until you get a positive number.
[tex]-\frac{\pi}{3}[/tex] + [tex]\frac{6\pi}{3}[/tex] = [tex]\frac{5\pi}{3}[/tex]
Now, look at the Unit Circle to find that it is located in Quadrant II (at 150°)
*************************************************************************
Answers: IV, positive, [tex]\frac{\pi}{4}[/tex], B, [tex]\frac{\sqrt{2}} {2}[/tex]
