Respuesta :

wegnerkolmp2741o

slope = (y2-y1)/(x2-x1)

m =(-1-5)/(-3-4)

m =(-6)/(-7)

m=6/7

point slope form

y-y1 = m(x-x1)

y-5 = (6/7) (x-4)


gmany

The slope-point form:

[tex]y-y_1=m(x-x_1)\\\\m=\dfrac{y_2-y_1}{x_2-x_1}[/tex]

We have two points (4, 5) and (-3, -1). Substitute:

[tex]m=\dfrac{-1-5}{-3-4}=\dfrac{-6}{-7}=\dfrac{6}{7}[/tex]

For point (4, 5):

[tex]y-5=\dfrac{6}{7}(x-4)[/tex]

For point (-3, -1):

[tex]y-(-1)=\dfrac{6}{7}(x-(-3))\\\\y+1=\dfrac{6}{7}(x+3)[/tex]