bznnxx
bznnxx
16-10-2018
Mathematics
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[tex]6 < x + 5 \leqslant 11[/tex]
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gmany
gmany
22-10-2018
[tex]6 < x+5\leq11\qquad|\text{subtract 5 from every sides}\\\\1 < x\leq6\to x\in(1,\ 6][/tex]
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