dada7742
dada7742 dada7742
  • 12-09-2018
  • Mathematics
contestada

What is the length of the hypotenuse, x f (20, 21, x) is a Pythagorean triple

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jdoe0001 jdoe0001
  • 12-09-2018

[tex]\bf \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies c=\sqrt{a^2+b^2} \qquad \begin{cases} c=\stackrel{hypotenuse}{x}\\ a=\stackrel{adjacent}{20}\\ b=\stackrel{opposite}{21}\\ \end{cases} \\\\\\ x=\sqrt{20^2+21^2}\implies x=\sqrt{841}\implies x=29[/tex]

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228yvngin 228yvngin
  • 12-11-2020

Answer:

B) - 29

Step-by-step explanation:

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