see the attached picture with letters to better understand the problem
Part 8) we know that The angle bisectors of a triangle intersect in a point (incenter) that is equidistant from the three sides of the triangle so OF=OD=OE-----> are the radii of the inscribed circle
the triangle ODB and the triangle OBE are congruent so
applying the Pythagoras Theorem OB²=OD²+DB²------> solve for OD OD²=OB²-DB²------> (√28)²-5²-----> OD²=28-25-----> OD=√3 units
radius is equal to OD therefore
the answer part 8) is radius is √3 units
Part 9) What is the value of x?
we know that in the quadrilateral FOEC the sum of the internal angles must be equal to 360 degrees so 360=90+90+60+x x=360-240 x=120°
