chloerk02 chloerk02

12-06-2018
Mathematics

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1/3(x+3) - 2/x+3, where x is not equal to negative 3

Respuesta :

13-06-2018

If [tex]x\neq 3[/tex], then

[tex] \frac{1}{3(x+3)} - \frac{2}{x+3} = \frac{1\cdot 1-2\cdot 3}{3(x+3)} = \frac{-5}{3(x+3)} =- \frac{5}{3(x+3)} [/tex].

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