makaylarainer makaylarainer

14-05-2018
Mathematics

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Q and R are not mutually exclusive events. p (q) = 3/5 p(r) = 1/3 and p ( q and r)= 1/5 find P(Q or R).

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LammettHash LammettHash

14-05-2018

Recall the inclusion/exclusion principle:

[tex]\mathbb P(Q\cup R)=\mathbb P(Q)+\mathbb P(R)-\mathbb P(Q\cap R)[/tex]

which means

[tex]\mathbb P(Q\text{ or }R)=\dfrac35+\dfrac13-\dfrac15=\dfrac{11}{15}[/tex]

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